Q: Why doesn't sizeof properly report the size of an array when the array is a parameter to a function? I have a test routine
f(char a[10])
{
int i = sizeof(a);
printf("%d\n", i);
}
and it prints
4, not 10.
A: The compiler pretends that the array parameter was declared as a pointer (that is, in the example, as char *a; see question 6.4), and sizeof reports the size of the pointer. See also questions 1.24 and 7.28.
References:
H&S Sec. 7.5.2 p. 195
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