Q: I had the definition char a[6] in one source file, and in another I declared extern char *a. Why didn't it work?
A: In one source file you defined an array of characters and in the other you declared a pointer to characters. The declaration extern char *a does not declare an array and therefore does not match the actual definition. The type pointer-to-type-T is not the same as array-of-type-T. Use extern char a[].
References:
ISO Sec. 6.5.4.2
CT&P Sec. 3.3 pp. 33-4, Sec. 4.5 pp. 64-5
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