Q: What is the most efficient way to count the number of bits which are set in an integer?
A: Many ``bit-fiddling'' problems like this one can be sped up and streamlined using lookup tables (but see question 20.13). Here is a little function which computes the number of bits in a value, 4 bits at a time:
static int bitcounts[] = {0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4}; int bitcount(unsigned int u) { int n = 0; for(; u != 0; u >>= 4) n += bitcounts[u & 0x0f]; return n; }